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Quadratic Equation-graphical solutions
School Name:
Teacher's Name:
Academic Session:
Term:
Week:

LESSON PLAN

SS 2 LESSON PLAN WEEK ..........

................... - ...................

DATE: ...................CLASS: SS 2
TIME: ...................PERIOD: ...................
DURATION: 40 minutesNO IN CLASS: 0
AVERAGE AGE: 0SEX: ........
SUBJECT: MathematicsTHEME: Algebraic Methods and Graphical Representation
TOPIC: Quadratic Equation-graphical solutionsSUB TOPIC: Graphical Solutions of Quadratic Equations
RATIONAL:
Understanding quadratic equations and their graphical solutions is fundamental in mathematics, providing a visual interpretation of algebraic concepts. This skill is crucial for advanced studies in science, engineering, and economics, where models often involve quadratic relationships. It also helps students develop critical thinking and problem-solving abilities by connecting algebraic manipulation with graphical analysis.
PREVIOUS KNOWLEDGE:
- Basic plotting of linear graphs
- Substitution of values into algebraic expressions
- Understanding of coordinates and Cartesian plane
- Solving simple linear equations
LEARNING MATERIALS:
- Graph boards/graph paper
- Rulers
- Pencils
- Scientific calculators (optional)
PRESENTATION:
STEPS/TIMETEACHER'S ACTIVITIESSTUDENT'S ACTIVITIESLEARNING POINTS
Step 1: 5 minutes - Introduction and ReviewThe teacher will greet the class and briefly review what a quadratic equation is, asking one student to state its general form. The teacher will then introduce the topic of graphical solutions, explaining that today's lesson will focus on how to find the roots of a quadratic equation by plotting its graph. The teacher will ask the class what they remember about plotting points on a graph.Students will respond to questions about quadratic equations and plotting points. One student will state the general form of a quadratic equation.Recall definition and general form of quadratic equations; activate prior knowledge on plotting.
Step 2: 15 minutes - Constructing Table of Values and PlottingThe teacher will present a quadratic equation, e.g., $y = x^2 - 4x + 3$. The teacher will guide the class through constructing a table of values for $x$ from -2 to 6. The teacher will demonstrate how to substitute values of $x$ into the equation to find corresponding $y$ values. After completing the table, the teacher will demonstrate how to plot these points on a graph paper, emphasizing accurate scaling and labeling of axes. The teacher will then connect the points to form a smooth curve (parabola).

| x | -2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|---|---|
| $x^2$ | 4 | 1 | 0 | 1 | 4 | 9 | 16 | 25 | 36 |
| $-4x$ | 8 | 4 | 0 | -4 | -8 | -12 | -16 | -20 | -24 |
| $+3$ | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 |
| y | 15 | 8 | 3 | 0 | -1 | 0 | 3 | 8 | 15 |

[graph]
title: Plotting y = x^2 - 4x + 3
x-range: -2, 6
function: x^2 - 4*x + 3 | label: y = x^2 - 4x + 3
[/graph]
Students will actively participate in calculating $y$ values for the table. They will observe the teacher's demonstration of plotting points and drawing the curve, asking clarifying questions.Learn to construct a table of values and accurately plot the graph of a quadratic equation.
Step 3: 10 minutes - Identifying Roots from the GraphThe teacher will explain that the roots of the quadratic equation are the $x$-values where the graph intersects the $x$-axis (i.e., where $y=0$). Using the graph plotted in Step 2, the teacher will point out the intersection points and read off the corresponding $x$-values. For the example $y = x^2 - 4x + 3$, the teacher will show that the graph intersects the $x$-axis at $x=1$ and $x=3$. The teacher will emphasize that these are the solutions to the equation $x^2 - 4x + 3 = 0$.Students will identify the points of intersection on the $x$-axis from the plotted graph and state the roots of the equation.Understand that roots are $x$-intercepts and how to read them from the graph.
Step 4: 10 minutes - Application and ConclusionThe teacher will present a new quadratic equation, e.g., $y = x^2 + x - 6$, and ask two volunteers to come to the board to construct a table of values and plot the graph. The rest of the class will work in pairs to do the same. The teacher will circulate, providing support and checking for understanding. After the graphs are drawn, the teacher will ask students to identify the roots. The teacher will then summarize the key steps for solving quadratic equations graphically and assign homework.

[graph]
title: Plotting y = x^2 + x - 6
x-range: -4, 3
function: x^2 + x - 6 | label: y = x^2 + x - 6
[/graph]
Students will work individually or in pairs to construct tables of values, plot graphs, and identify roots for a new quadratic equation. Two volunteers will demonstrate on the board.Apply the learned steps to solve a new quadratic equation graphically and reinforce understanding.
EVALUATION:
1. What is the shape of the graph of a quadratic equation?
2. How do you find the roots of a quadratic equation from its graph?
3. Plot the graph of $y = x^2 - 1$ for $x$ from -3 to 3 and state its roots.
CONCLUSION:
Today, we learned how to solve quadratic equations by plotting their graphs. This method provides a visual way to understand the solutions, which are the points where the parabola intersects the $x$-axis. Mastering this skill is important for visualizing mathematical relationships.
CONSOLIDATION:
In pairs, students will discuss one real-life scenario where understanding quadratic graphs could be useful.
DIFFERENTIATION:
Tier 1 (Support): Provide pre-filled tables of values for students to just plot and identify roots.
Tier 2 (Core): Students work independently to construct tables, plot graphs, and find roots.
Tier 3 (Challenge): Students explore equations with no real roots or one repeated root, discussing what the graph would look like.
CROSS-CURRICULAR LINKS:
Physics (projectile motion, e.g., throwing a stone)
Economics (profit maximization, cost functions)
ADDITIONAL RESOURCES:
New General Mathematics for SS 2 by J.B. Channon et al.
WAEC Past Questions on Quadratic Equations.
Online graphing tools like Desmos for visual demonstration.
ASSESSMENT CRITERIA:
Emerging: Can construct a partial table of values and attempt to plot some points.
Proficient: Can accurately construct a table of values, plot the graph, and identify roots with minor errors.
Advanced: Can accurately construct tables, plot graphs, identify roots, and apply graphical solutions to solve real-world problems.
HOMEWORK:
Students will complete the assignment questions on graph paper, estimated to take 20 minutes.
TEACHER'S REFLECTION:
Were the students engaged throughout the lesson?
Did all students successfully plot a quadratic graph and identify the roots?
What common misconceptions arose, and how can I address them next time?

STUDENT NOTE

Mathematics - SS 2 - Quadratic Equation-graphical solutions

## Learning Objectives By the end of this lesson, students should be able to: 1. Define a quadratic equation and identify its graphical representation. 2. Construct a table of values for a given quadratic equation over a specified range. 3. Plot the graph of a quadratic equation accurately on a Cartesian plane. 4. Determine the roots (solutions) of a quadratic equation from its graph. 5. Solve simple real-life problems involving quadratic equations graphically. ## 1. Introduction to Quadratic Equations and Graphs > **Definition:** A quadratic equation is a polynomial equation of the second degree, meaning it contains at least one term in which the unknown variable is raised to the power of two. Its general form is $ax^2 + bx + c = 0$, where $a$, $b$, and $c$ are constants and $a \neq 0$. When we plot a quadratic equation on a graph, it always forms a U-shaped curve called a parabola. The direction of the parabola (opening upwards or downwards) depends on the sign of the coefficient $a$. If $a > 0$, the parabola opens upwards; if $a < 0$, it opens downwards. The points where the parabola crosses the $x$-axis are called the roots or solutions of the equation. ## 2. Constructing a Table of Values To plot the graph of a quadratic equation, we first need to create a table of values. This involves choosing a range of $x$-values and substituting each into the equation to find the corresponding $y$-values. For example, if we have the equation $y = x^2 - 4x + 3$, we can choose $x$-values from -2 to 6. **Steps to construct a table of values:** 1. Choose a suitable range of $x$-values (e.g., from -2 to 6). 2. For each $x$-value, substitute it into the quadratic equation to calculate the corresponding $y$-value. 3. Record the $(x, y)$ pairs in a table. | x | -2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 | |---|---|---|---|---|---|---|---|---|---| | $x^2$ | 4 | 1 | 0 | 1 | 4 | 9 | 16 | 25 | 36 | | $-4x$ | 8 | 4 | 0 | -4 | -8 | -12 | -16 | -20 | -24 | | $+3$ | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | | y | 15 | 8 | 3 | 0 | -1 | 0 | 3 | 8 | 15 | ## 3. Plotting the Graph and Finding Roots Once you have your table of values, you can plot the points on a Cartesian plane. Remember to choose an appropriate scale for both the $x$-axis and $y$-axis. After plotting all the points, draw a smooth curve through them to form the parabola. The points where your parabola intersects the $x$-axis (where $y=0$) are the roots of the quadratic equation. These are the solutions to $ax^2 + bx + c = 0$. [graph] title: Graph of y = x^2 - 4x + 3 x-range: -2, 6 y-range: -2, 16 function: x^2 - 4*x + 3 | label: y = x^2 - 4x + 3 [/graph] In the graph above, the curve intersects the $x$-axis at $x=1$ and $x=3$. Therefore, the roots of the equation $x^2 - 4x + 3 = 0$ are $x=1$ and $x=3$. ## Worked Examples **Example 1:** Solve the equation $x^2 - 2x - 3 = 0$ graphically for $x$ from -2 to 4. <span class="badge medium">MEDIUM</span> Solution: Step 1: Construct a table of values for $y = x^2 - 2x - 3$. | x | -2 | -1 | 0 | 1 | 2 | 3 | 4 | |---|---|---|---|---|---|---|---|---| | $x^2$ | 4 | 1 | 0 | 1 | 4 | 9 | 16 | | $-2x$ | 4 | 2 | 0 | -2 | -4 | -6 | -8 | | $-3$ | -3 | -3 | -3 | -3 | -3 | -3 | -3 | | y | 5 | 0 | -3 | -4 | -3 | 0 | 5 | Step 2: Plot the points and draw the graph. [graph] title: Graph of y = x^2 - 2x - 3 x-range: -2, 4 y-range: -5, 6 function: x^2 - 2*x - 3 | label: y = x^2 - 2x - 3 [/graph] Step 3: Identify the roots from the graph. The graph intersects the $x$-axis at $x = -1$ and $x = 3$. Answer: The roots are $x = -1$ and $x = 3$. **Example 2:** A ball is thrown upwards. Its height $h$ (in meters) after $t$ seconds is given by the equation $h = 10t - t^2$. Use a graph to find when the ball hits the ground. <span class="badge exam">EXAM</span> Solution: Step 1: The ball hits the ground when $h=0$. So, we need to solve $10t - t^2 = 0$ graphically. Construct a table of values for $h = 10t - t^2$ for $t$ from 0 to 10. | t | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | |---|---|---|---|---|---|---|---|---|---|---|---| | $10t$ | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 | | $-t^2$ | 0 | -1 | -4 | -9 | -16 | -25 | -36 | -49 | -64 | -81 | -100 | | h | 0 | 9 | 16 | 21 | 24 | 25 | 24 | 21 | 16 | 9 | 0 | Step 2: Plot the points and draw the graph. [graph] title: Height of ball h = 10t - t^2 x-label: Time (t) in seconds y-label: Height (h) in meters x-range: 0, 10 y-range: 0, 26 function: 10*x - x^2 | label: h = 10t - t^2 [/graph] Step 3: Identify when $h=0$ from the graph. The graph intersects the $t$-axis (where $h=0$) at $t=0$ and $t=10$. Answer: The ball hits the ground at $t=0$ seconds (when it is thrown) and at $t=10$ seconds. ## Board Summary (Quick Revision Notes) +------------------------------------------------+ | QUADRATIC EQUATION - GRAPHICAL SOLUTIONS | +------------------------------------------------+ | CONCEPT: Roots are x-intercepts of parabola. | | KEY STEPS: | | 1. Form table of values (x, y). | | 2. Plot points and draw smooth curve. | | 3. Read x-values where curve crosses x-axis.| | EXAM FOCUS: Accuracy in plotting and reading. | +------------------------------------------------+ ## Evaluation Questions (Class Work) 1. <span class="badge easy">EASY</span> What is the general form of a quadratic equation? 2. <span class="badge easy">EASY</span> If the graph of $y = ax^2 + bx + c$ opens downwards, what can you say about the value of $a$? 3. <span class="badge medium">MEDIUM</span> Construct a table of values for $y = x^2 - 6x + 5$ for $x$ from 0 to 6. 4. <span class="badge medium">MEDIUM</span> Using your table from Q3, if you were to plot the graph, what would be the roots of the equation $x^2 - 6x + 5 = 0$? **Answers:** 1. $ax^2 + bx + c = 0$ 2. $a < 0$ 3. | x | 0 | 1 | 2 | 3 | 4 | 5 | 6 | |---|---|---|---|---|---|---|---| | y | 5 | 0 | -3 | -4 | -3 | 0 | 5 | 4. $x=1$ and $x=5$ ## Assignment Questions (Homework) 1. <span class="badge easy">EASY</span> For the equation $y = x^2 - x - 2$, what are the $y$-values when $x=0$, $x=1$, and $x=2$? 2. <span class="badge medium">MEDIUM</span> Plot the graph of $y = x^2 - x - 2$ for $x$ from -2 to 3. (Use graph paper). 3. <span class="badge medium">MEDIUM</span> From your graph in Q2, determine the roots of the equation $x^2 - x - 2 = 0$. 4. <span class="badge exam">EXAM</span> The profit $P$ (in thousands of Naira) of a small business is modeled by the equation $P = 10x - x^2$, where $x$ is the number of items sold (in hundreds). Plot the graph of $P$ against $x$ for $x$ from 0 to 10 and determine the number of items sold for which the profit is zero. **Answers:** 1. $y=-2$, $y=-2$, $y=0$ 2. (Graph should show a parabola opening upwards, passing through $(-1,0)$ and $(2,0)$) 3. $x=-1$ and $x=2$ 4. (Graph should show a parabola opening downwards, passing through $(0,0)$ and $(10,0)$). Profit is zero when $x=0$ (0 items) and $x=10$ (1000 items).